Note :- This is a new feature in ASP.NET 2.0
By default, button controls in ASP.NET pages post back to the same page that contains the
button, where you can write an event handler for the post. In most cases this is the desired
behavior, but occasionaly you will also want to be able to post to another page in your
application. The Server.Transfer method can be used to move between pages, however the URL
does not change. Instead, the cross page-posting feature in ASP.NET 2.0 allows you to fire a
normal post back to a different page in the application. In the target page, you can then access the
values of server controls in the source page that initiated the post back.
To use cross page posting, you can set the PostBackUrl property of a Button, LinkButton or
ImageButton control, which specifies the target page. In the target page, you can then access the
PreviousPage property to retrieve values from the source page. By default, the PreviousPage
property is of type Page, so you must access controls using the FindControl method. You can also
enable strongly-typed access to the source page by setting the @PreviousPageType directive in
the target page to the virtual path or Type name of the source page.
Here is a systematic guide for implementing the cross-page post back using controls that
implement the IButtonControl interface.
• Create a Web Form and insert a Button control on it using the VS .NET designer.
• Set the button's PostBackUrl property to the Web Form you want to post back. For
instance in this case it is "nextpage.aspx"
When the PostBackUrl property of the IButtonControl is set, the ASP.NET framework binds thecorresponding HTML element to new JavaScript function named
WebForm_DoPostBackWithOptions. The corresponding HTML rendered by the ASP.NET 2.0
will look like this:
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